Blog #2

THE GRAVITRON
Description of ride: You enter the spaceship and lay on the inside of its walls it starts to spin and retains a constant velocity. It is spinning so fast it makes you feel heavy, like you are being pushed with such great force that you struggle to move.
NEWTONS LAW OF UNIVERSAL GRAVITATION
NLUG shows that even though the mass of the objects are a mass of heavy or light weight it is not possible for an object to appear to be weightless, even if the masses are the same. The force of gravity is always constant meaning and object will have weight since a force can act upon it. All objects have to have some magnitude of mass in order to have movement or a force that makes it feel weightless or heavy.
ex:
equation: Fg= G(m1)(m2)/d^2
you have two masses & G= universal gravitational constant
m1: .021 kg
m2: .021 kg
G: 6.67 x 10^-11
6.67 x 10^-11(.021)(.021)/(1)^2= 2.94147 x 10^-14
= .0000000000000294147 

Edward has a mass of 59.3kg and Bella has a mass of 52.6kg. Edward and Bella are standing 10.3m apart in a mass-less meadow. Bella looks up and sees Edward. Shes feels and attraction.
If the gravitational constant is 6.67 x 10^-11 find its magnitude in the unit of N.  
equation: Fg= G(m1)(m2)/d^2 D= 10.3
m1= 59.3
m2= 52.6
G= 6.67 x 10^-11

6.67 x 10^-11(59.3)(52.6)/ (10.3)^2
= 1.961064247 x 10^-9
= .000000001961064247

If an object retains a constant speed. Is there a net force on the object as it rounds a curve during its travel?
(a) yes
(b) no
(c) possibly
ans (b) 

What does NLUG stand for and what is the universal gravitation constant?
Newtons law of Universal Gravitation & G= 6.67 x10^-11
 

Blog #1 Part 2

If Fg=Fn and Fa=FA what is the objects possible speed?
a. 179N
b.constant
c. no motion
d. 12kg

Answer b&c
If an object FBD all are equal it is possible that the object could be containing a constant speed or not having any motion at all. When all the forces cancel out it is called an equal librium.

A man is holding four bags of sand from a rope that weight a total of 136N. How much tension is exerted in each strand?

a. 136N

b. 30N

c. 34N

e. none

Answer:  C; 34N 

You take the total weight(N) and then divide it by the number of strings that is holding to find their individual tension.

A box is pulled to the right with a force of 89N, to the left with a force 119N, upward with a force 450N, and downward with a force 139.5N.
What is the net external force in the x direction?
(ans) -30N
The answer must be a negative number because the force is what is making it move that direction. It took more force to move the object in the right direction that it took when the box was actually moving in the right direction.

What is the external force in the y direction?
(ans) 310.5N

Blog #1

Week 7

 In physics the vx= a harmonic motion. At any given point the projectile of vx will always be the same on any point of travel of an object. The amplitude of the distance will always be a constant number just like the vx will always remain constant. The amplitude could be better described as the maximun displacment of the highest point on the oscillation. The horses on a carousel are a good example of harmonic motion. They all move together at a constant speed and the same distance. The vx is always the same when you take its absolute value. It doesn't matter at what  point the object us in its time of travel the vx will ALWAYS be the same, the only factors that will change are the vy and v.

vx= velocity in x direction
vy= velocity in y direction
v= velocity

A bottle rocket is launched from the ground.  The rocket launcher wants to know what the speed of the rocket is going when it hits the ground but he only know the velocity of x when its is in the middle of its travel which is 25 m/s. By looking at the image determine what is the velocity of the x value during its travel includig the time it hits the ground.

Answer: 25 m/s

A soccer ball is kicked with and intial velocity of 20 m/s at an angle of 30 degrees with the horozontal. Determine the time of flight, the horozontal distance.

Answer: The flight time of the ball was 2.04 seconds and the horozontal distance what 35.35